# the average oxidation state of sulphur in na2s4o6

The average oxidation state of sulphur in sodium tetrathonate `(Na_(2)S_(4)O_(6))` is : Apne doubts clear karein ab Whatsapp (8 400 400 400) par bhi. let x= oxidation number of sulphur, and +1 is oxidation number of Na, -2 is oxidation number of O, also assume total charge on compound = 0 then solving we get. S atoms namely S 1 and S 4 have oxidation number +5 each.. It is defined as being the charge that an atom would have if all bonds were ionic. Education Minister live session on 03 Dec 2020 with students and parents regarding upcoming competitive & board examinations. 5.2k SHARES. Menu. Calculate the oxidation number of S in Na 2 S 4 O 6. VITEEE 2021 registrations started, check the application process. 7.23, center left) is the average of two sulfur atoms with different oxidation states. O has the oxidation number -II. The sum of all oxidation numbers should be zero (if it not a ion): 2 - 12 = -10. Common oxidation states of sulfur range from −2 to +6. The oxidation state +2.5 is just the average oxidation state for the S atom.
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